What is (\partial)/(\partial y)(5x^2+y^2) ?

The answer to (\partial)/(\partial y)(5x^2+y^2) is 2y

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(\partial)/(\partial y)(5x^2+y^2)

\frac{\partial}{\partial y} (5 x^{2} + y^{2})

2 y

Solution steps

\frac{\partial}{\partial y} (5 x^{2} + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (5 x^{2}) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (5 x^{2}) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 + 2 y

Simplify

= 2 y

y = 0, y = 9 - x^{2}

\int cos^{2} (x) + 1 d x

y = - 4 lo g_{5} (x)

\frac{d}{d x} (e^{3 x} + e^{x + e^{- 2 x}})

\int_{1}^{e} t^{2} ln (t) d t

What is (\partial)/(\partial y)(5x^2+y^2) ?
The answer to (\partial)/(\partial y)(5x^2+y^2) is 2y