What is the limit as x approaches 0+of arctan(ln(x)) ?

The limit as x approaches 0+of arctan(ln(x)) is -pi/2

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limit as x approaches 0+of arctan(ln(x))

x \to 0 + lim (arctan (ln (x)))

- \frac{π}{2}

Decimal Notation

- 1.57079 \dots

Solution steps

x \to 0 + lim (arctan (ln (x)))

Apply the Limit Chain Rule:

- \frac{π}{2}

= - \frac{π}{2}

\frac{d v}{d x} - \frac{1}{x} v = 8

\frac{ln ( x )}{e ^{x}}

x \to 0 lim (\frac{5}{x} - \frac{5}{∣ x ∣})

f (x) = x, g (x) = x, [0, 2]

\int_{2}^{25} sin (2 x) d x

What is the limit as x approaches 0+of arctan(ln(x)) ?
The limit as x approaches 0+of arctan(ln(x)) is -pi/2