What is the integral of sin(piy) ?

The integral of sin(piy) is -1/pi cos(piy)+C

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integral of sin(piy)

\int sin (π y) d y

- \frac{1}{π} cos (π y) + C

Solution steps

\int sin (π y) d y

Apply u-substitution

: \int sin (u) \frac{1}{π} d u

= \int sin (u) \frac{1}{π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{π} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{π} (- cos (u))

Substitute back

u = π y

= \frac{1}{π} (- cos (π y))

Simplify

= - \frac{1}{π} cos (π y)

Add a constant to the solution

= - \frac{1}{π} cos (π y) + C

\frac{\partial}{\partial x} (sin (x^{2} - y^{2}))

11 x^{2} - 4 x

y^{^{'}} = \frac{( sec ( y ) )}{( x - 4 ) ^{2}}

\frac{d y}{d x} = \frac{2 - e ^{x}}{3 + 2 y}, y (0) = 0

\int_{0}^{1} (x + 1)^{2} d x