What is the d/(dt)(sin(5t)) ?

The d/(dt)(sin(5t)) is cos(5t)*5

What is the first d/(dt)(sin(5t)) ?

The first d/(dt)(sin(5t)) is cos(5t)*5

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\frac{d}{d t} (sin (5 t))

cos (5 t) \cdot 5

Solution steps

\frac{d}{d t} (sin (5 t))

Apply the chain rule:

cos (5 t) \frac{d}{d t} (5 t)

= cos (5 t) \frac{d}{d t} (5 t)

\frac{d}{d t} (5 t) = 5

= cos (5 t) \cdot 5

y^{^{'}} = 2 x - 3 y

\int 2 (tan^{2} (x) + tan^{4} (x)) d x

\int x arccot (x) d x

f^{^{''}} (x) = x^{- \frac{3}{2}}, f^{^{'}} (4) = 7, f (0) = 0

\frac{d}{d x} (\frac{2}{( x - 1 ) ^{3}})