What is the integral from 1 to-1 of x^2 ?

The integral from 1 to-1 of x^2 is -2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to-1 of x^2

\int_{1}^{- 1} x^{2} d x

- \frac{2}{3}

Decimal

- 0.66666 \dots

Solution steps

\int_{1}^{- 1} x^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 1}^{1} x^{2} d x

Apply the Power Rule

= - [\frac{x ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= - \frac{2}{3}

\int_{x^{2}}^{x} (x^{2} + y^{2}) d y

\int_{- 1}^{1} x^{7} d x

\int_{0}^{1} x (x^{2} + 6) d x

\int_{- 1}^{3} (3 x - 8) (x + 3) d x

\int_{0}^{4} 5 x^{2} d x

What is the integral from 1 to-1 of x^2 ?
The integral from 1 to-1 of x^2 is -2/3