What is the solution for (dy)/(dx)= 1/(sec^2(y)) ?

The solution for (dy)/(dx)= 1/(sec^2(y)) is y=arctan(x+c_{1})+pin

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(dy)/(dx)= 1/(sec^2(y))

\frac{d y}{d x} = \frac{1}{sec ^{2} ( y )}

y = arctan (x + c_{1}) + πn

Solution steps

\frac{d y}{d x} = \frac{1}{sec ^{2} ( y )}

Solve separable ODE:

y = arctan (x + c_{1}) + πn

y = arctan (x + c_{1}) + πn

\frac{d}{d x} (\frac{x ^{4} + 2}{ln ( x )})

\int \frac{x}{e ^{4 x}} d x

n = 1 \sum \infty \frac{2}{9 ^{n}}

3 x - 2 x^{2}

x \to 0 lim ((e^{- \frac{1}{x}})^{x})

What is the solution for (dy)/(dx)= 1/(sec^2(y)) ?
The solution for (dy)/(dx)= 1/(sec^2(y)) is y=arctan(x+c_{1})+pin