What is (\partial)/(\partial y)(3x^2y+4xy^2) ?

The answer to (\partial)/(\partial y)(3x^2y+4xy^2) is 3x^2+8xy

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(\partial)/(\partial y)(3x^2y+4xy^2)

\frac{\partial}{\partial y} (3 x^{2} y + 4 x y^{2})

3 x^{2} + 8 x y

Solution steps

\frac{\partial}{\partial y} (3 x^{2} y + 4 x y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2} y) + \frac{\partial}{\partial y} (4 x y^{2})

\frac{\partial}{\partial y} (3 x^{2} y) = 3 x^{2}

\frac{\partial}{\partial y} (4 x y^{2}) = 8 x y

= 3 x^{2} + 8 x y

\int e^{x} 8 + e^{x} d x

y^{^{'}} = \frac{( e ^{(x - y)} )}{1 + e ^{x}}

\int e^{- \frac{x}{10}} d x

\frac{d}{d x} (20 - 2 x)

\frac{d}{d x} (\frac{x ^{4}}{8} ln (x) - \frac{x ^{4}}{32})

What is (\partial)/(\partial y)(3x^2y+4xy^2) ?
The answer to (\partial)/(\partial y)(3x^2y+4xy^2) is 3x^2+8xy