What is the derivative of 1/8 y^3 ?

The derivative of 1/8 y^3 is (3y^2)/8

What is the first derivative of 1/8 y^3 ?

The first derivative of 1/8 y^3 is (3y^2)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{1}{8} y^{3}

\frac{3 y ^{2}}{8}

Solution steps

\frac{d}{d y} (\frac{1}{8} y^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d y} (y^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} \cdot 3 y^{3 - 1}

Simplify

\frac{1}{8} \cdot 3 y^{3 - 1} : \frac{3 y ^{2}}{8}

= \frac{3 y ^{2}}{8}

\frac{d ^{2}}{d x ^{2}} (5 csc (x))

ln (\frac{1 + 2 x}{1 - 3 x})

(4.5) (1.2)

\frac{d}{d x} (\frac{x ^{3}}{sin ( x )})

y = x^{2} - 2 x + 3, (2, 3)

What is the derivative of 1/8 y^3 ?
The derivative of 1/8 y^3 is (3y^2)/8
What is the first derivative of 1/8 y^3 ?
The first derivative of 1/8 y^3 is (3y^2)/8