What is the integral from 1.5 to 2.5 of 9800(7-y)(1) ?

The integral from 1.5 to 2.5 of 9800(7-y)(1) is 49000

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integral from 1.5 to 2.5 of 9800(7-y)(1)

\int_{1.5}^{2.5} 9800 (7 - y) (1) d y

49000

Solution steps

\int_{1.5}^{2.5} 9800 (7 - y) \cdot 1 d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9800 \cdot 1 \cdot \int_{1.5}^{2.5} 7 - y d y

Simplify

= 9800 \cdot \int_{1.5}^{2.5} 7 - y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 9800 (\int_{1.5}^{2.5} 7 d y - \int_{1.5}^{2.5} y d y)

\int_{1.5}^{2.5} 7 d y = 7

\int_{1.5}^{2.5} y d y = 2

= 9800 (7 - 2)

Simplify

= 49000

\frac{1}{s ^{2} + 16}

\frac{1}{s ( s ^{2} + s + \frac{5}{4} )}

e^{x - 1}

\frac{\partial}{\partial x} (2 x y + 5 x^{2})

f (x) = \frac{x ^{2}}{x + 9}, at x = 1

What is the integral from 1.5 to 2.5 of 9800(7-y)(1) ?
The integral from 1.5 to 2.5 of 9800(7-y)(1) is 49000