What is the limit as x approaches 0 of ((1+x)^2)/x ?

The limit as x approaches 0 of ((1+x)^2)/x is diverges

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limit as x approaches 0 of ((1+x)^2)/x

x \to 0 lim (\frac{( 1 + x ) ^{2}}{x})

diverges

Solution steps

x \to 0 lim (\frac{( 1 + x ) ^{2}}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{( 1 + x ) ^{2}}{x}) = \infty

x \to 0 - lim (\frac{( 1 + x ) ^{2}}{x}) = - \infty

= diverges

\int \frac{( ln ( x ) ) ^{2} + 1}{ln ( x )} d x

y^{^{'}} = \frac{e ^{x - y}}{e ^{x} + 1}

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + k y = 0

y^{^{'}} + 3 x e^{y} = 0

n = 1 \sum \infty \frac{3 ^{n}}{n 2 ^{n}}

What is the limit as x approaches 0 of ((1+x)^2)/x ?
The limit as x approaches 0 of ((1+x)^2)/x is diverges