What is the tangent of y=-6/x ,\at x=-4 ?

The tangent of y=-6/x ,\at x=-4 is y= 3/8 x+3

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tangent of y=-6/x ,\at x=-4

tangent of

y = - \frac{6}{x}, at x = - 4

y = \frac{3}{8} x + 3

Solution steps

Find the tangent point:

(- 4, \frac{3}{2})

Find the slope of

y = - \frac{6}{x} : \frac{d y}{d x} = \frac{6}{x ^{2}}

Compute the slope of

y = - \frac{6}{x}

x = - 4 : m = \frac{3}{8}

Find the line with slope m=

\frac{3}{8}

and passing through

(- 4, \frac{3}{2}) : y = \frac{3}{8} x + 3

y = \frac{3}{8} x + 3

\frac{d}{d x} (cot^{2} (3 x))

n = 5 \sum \infty e^{3 - 4 n}

y^{^{''}} + 4 π^{2} y = cos^{3} (2 π x)

\int 2 x I n x^{2} d x

\frac{d}{d x} (\frac{8 ^{x}}{7 ^{x}})

What is the tangent of y=-6/x ,\at x=-4 ?
The tangent of y=-6/x ,\at x=-4 is y= 3/8 x+3