integral from 0 to 1 of 144t^2+224t+104

Lösung

\int_{0}^{1} 144 t^{2} + 224 t + 104 d t

264

Schritte zur Lösung

\int_{0}^{1} 144 t^{2} + 224 t + 104 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 144 t^{2} d t + \int_{0}^{1} 224 t d t + \int_{0}^{1} 104 d t

\int_{0}^{1} 144 t^{2} d t = 48

\int_{0}^{1} 224 t d t = 112

\int_{0}^{1} 104 d t = 104

= 48 + 112 + 104

Vereinfache

= 264

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