What is the d/(dq)(500q-(q^2)/(ln(q+300))) ?

The d/(dq)(500q-(q^2)/(ln(q+300))) is 500-(2qln(q+300)(q+300)-q^2)/(ln^2(q+300)(q+300))

What is the first d/(dq)(500q-(q^2)/(ln(q+300))) ?

The first d/(dq)(500q-(q^2)/(ln(q+300))) is 500-(2qln(q+300)(q+300)-q^2)/(ln^2(q+300)(q+300))

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\frac{d}{d q} (500 q - \frac{q ^{2}}{ln ( q + 300 )})

500 - \frac{2 q ln ( q + 300 ) ( q + 300 ) - q ^{2}}{ln ^{2} ( q + 300 ) ( q + 300 )}

Solution steps

\frac{d}{d q} (500 q - \frac{q ^{2}}{ln ( q + 300 )})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d q} (500 q) - \frac{d}{d q} (\frac{q ^{2}}{ln ( q + 300 )})

\frac{d}{d q} (500 q) = 500

\frac{d}{d q} (\frac{q ^{2}}{ln ( q + 300 )}) = \frac{2 q ln ( q + 300 ) ( q + 300 ) - q ^{2}}{ln ^{2} ( q + 300 ) ( q + 300 )}

= 500 - \frac{2 q ln ( q + 300 ) ( q + 300 ) - q ^{2}}{ln ^{2} ( q + 300 ) ( q + 300 )}

\frac{\partial}{\partial x} (tan (9 + 2 x^{2} y^{4} z^{2}))

\frac{d}{d x} ((2 - x)^{3})

\frac{1}{8} x, \frac{1}{x ^{2}}, x

x \to \infty lim (ln (5 x^{2} + 12 x - 6))

\int e^{9 x} sin (x) d x

What is the d/(dq)(500q-(q^2)/(ln(q+300))) ?
The d/(dq)(500q-(q^2)/(ln(q+300))) is 500-(2qln(q+300)(q+300)-q^2)/(ln^2(q+300)(q+300))
What is the first d/(dq)(500q-(q^2)/(ln(q+300))) ?
The first d/(dq)(500q-(q^2)/(ln(q+300))) is 500-(2qln(q+300)(q+300)-q^2)/(ln^2(q+300)(q+300))