What is the limit as x approaches 0 of (sin(4x))/6 ?

The limit as x approaches 0 of (sin(4x))/6 is 0

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limit as x approaches 0 of (sin(4x))/6

x \to 0 lim (\frac{sin ( 4 x )}{6})

0

Solution steps

x \to 0 lim (\frac{sin ( 4 x )}{6})

Plug in the value

x = 0

= \frac{sin ( 4 \cdot 0 )}{6}

Simplify

\frac{sin ( 4 \cdot 0 )}{6} : 0

= 0

\frac{\partial}{\partial y} (x e^{y^{2}} + y ln (x))

\int \frac{6}{( x - 4 ) ( x + 2 )} d x

y^{^{''}} + 81 y = sec^{2} (9 x)

(\frac{1}{4}, \frac{7}{8}), (4 \frac{1}{4}, 2 \frac{7}{8})

n = 0 \sum \infty \frac{1}{( 2 n + 1 ) ^{6}}

What is the limit as x approaches 0 of (sin(4x))/6 ?
The limit as x approaches 0 of (sin(4x))/6 is 0