What is the derivative of x^2+8x-2 ?

The derivative of x^2+8x-2 is 2x+8

What is the first derivative of x^2+8x-2 ?

The first derivative of x^2+8x-2 is 2x+8

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derivative of

x^{2} + 8 x - 2

2 x + 8

Solution steps

\frac{d}{d x} (x^{2} + 8 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (2) = 0

= 2 x + 8 - 0

Simplify

= 2 x + 8

x^{2} d y + 2 x y d x = 0

\frac{d ^{2}}{d x ^{2}} (- cos (x) ln (sec (x) + tan (x)))

\int \frac{10}{x ^{5}} d x

t y^{^{'}} + 2 y = \frac{2}{1 + t ^{2}}

What is the derivative of x^2+8x-2 ?
The derivative of x^2+8x-2 is 2x+8
What is the first derivative of x^2+8x-2 ?
The first derivative of x^2+8x-2 is 2x+8