What is the derivative of sqrt(3x+7) ?

The derivative of sqrt(3x+7) is 3/(2sqrt(3x+7))

What is the first derivative of sqrt(3x+7) ?

The first derivative of sqrt(3x+7) is 3/(2sqrt(3x+7))

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derivative of

3 x + 7

\frac{3}{2 3 x + 7}

Solution steps

\frac{d}{d x} (3 x + 7)

Apply the chain rule:

\frac{1}{2 3 x + 7} \frac{d}{d x} (3 x + 7)

= \frac{1}{2 3 x + 7} \frac{d}{d x} (3 x + 7)

\frac{d}{d x} (3 x + 7) = 3

= \frac{1}{2 3 x + 7} \cdot 3

Simplify

\frac{1}{2 3 x + 7} \cdot 3 : \frac{3}{2 3 x + 7}

= \frac{3}{2 3 x + 7}

- 2.25 cos (1.5 x)

\int_{0}^{33} (x - 1)^{- \frac{1}{5}} d x

y = (x^{2} + 4) (x^{3} - 4 x), (- 2, 0)

x \to - 2 lim (x^{2} - 3 x + 1)

\frac{π}{( s ^{2} + π ) ^{2}}

What is the derivative of sqrt(3x+7) ?
The derivative of sqrt(3x+7) is 3/(2sqrt(3x+7))
What is the first derivative of sqrt(3x+7) ?
The first derivative of sqrt(3x+7) is 3/(2sqrt(3x+7))