integral from 0 to 17pi of sin(x)

Lösung

\int_{0}^{17 π} sin (x) d x

2

Schritte zur Lösung

\int_{0}^{17 π} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{17 π}

Berechne die Grenzen:

2

= 2

\int_{1}^{x} 1 + t^{2} d t

\int_{0}^{3} 2 t d t

\int_{0}^{3} 2 y d y

\int_{1}^{x^{3}} \frac{g ( t )}{4 + t ^{2}} d t

\int_{1}^{7} (1 - x) (x - 7) d x