integral from-1 to 0 of x/(sqrt(4-x^2))

Lösung

\int_{- 1}^{0} \frac{x}{4 - x ^{2}} d x

- 2 + 3

Dezimale

- 0.26794 \dots

Schritte zur Lösung

\int_{- 1}^{0} \frac{x}{4 - x ^{2}} d x

Wende U-Substitution an

= \int_{3}^{4} - \frac{1}{2 u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int_{3}^{4} \frac{1}{u} d u

Wende die Potenzregel an

= - \frac{1}{2} [2 u^{\frac{1}{2}}]_{3}^{4}

Wende Radikal Regel an:

a^{\frac{1}{n}} = n a

= - \frac{1}{2} [2 u]_{3}^{4}

Berechne die Grenzen:

4 - 23

= - \frac{1}{2} (4 - 23)

Vereinfache

= - 2 + 3

\int_{0}^{2} 12 x^{3} 9 + x^{4} d x

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\int_{0}^{1} \frac{1}{x ^{0.9}} d x

\int_{0}^{1} (- x^{2} + x) d x

\int_{5}^{25} \frac{1}{x ( ln ( x ) ) ^{6}} d x