integral from 2 to 7 of tsqrt(t+2)

Lösung

\int_{2}^{7} t t + 2 d t

\frac{886}{15}

Dezimale

59.06666 \dots

Schritte zur Lösung

\int_{2}^{7} t t + 2 d t

Wende U-Substitution an

= \int_{4}^{9} (u - 2) u d u

Multipliziere aus

(u - 2) u : u^{\frac{3}{2}} - 2 u

= \int_{4}^{9} u^{\frac{3}{2}} - 2 u d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4}^{9} u^{\frac{3}{2}} d u - \int_{4}^{9} 2 u d u

\int_{4}^{9} u^{\frac{3}{2}} d u = \frac{422}{5}

\int_{4}^{9} 2 u d u = \frac{76}{3}

= \frac{422}{5} - \frac{76}{3}

Vereinfache

\frac{422}{5} - \frac{76}{3} : \frac{886}{15}

= \frac{886}{15}

\int_{- 1}^{2} (3 x^{2} - 2 x + 1) d x

\int_{- \frac{π}{4}}^{0} tan (x) d x

\int_{0}^{l n (6 x)} sin (7 e^{t}) d t

\int_{x}^{x^{2}} cos (t^{2}) d t

\int_{1}^{4} ∣ 2 x - 6 ∣ d x