integral from 0 to 2 of 4t-3t^2

Lösung

\int_{0}^{2} 4 t - 3 t^{2} d t

0

Schritte zur Lösung

\int_{0}^{2} 4 t - 3 t^{2} d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 4 t d t - \int_{0}^{2} 3 t^{2} d t

\int_{0}^{2} 4 t d t = 8

\int_{0}^{2} 3 t^{2} d t = 8

= 8 - 8

Vereinfache

= 0

\int_{0}^{2 - x} 2 - x - y d y

\int_{0}^{2} 4 x (x^{2} + 1)^{3} d x

\int_{1}^{2} e^{x - 1} - e d x

\int_{- 1}^{3} 3 - x d x

\int_{0}^{1} y \cdot 3 (1 - y)^{2} d y