integral from 0 to t of 1/(1+x^2)

Lösung

\int_{0}^{t} \frac{1}{1 + x ^{2}} d x

arctan (t)

Schritte zur Lösung

\int_{0}^{t} \frac{1}{1 + x ^{2}} d x

Nutze das gemeinsame Integral :

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{0}^{t}

Berechne die Grenzen:

arctan (t)

= arctan (t)

\int_{0}^{1} 4 x arctan (x) d x

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