integral from 0 to 2 of e^xx

Lösung

\int_{0}^{2} e^{x} x d x

e^{2} + 1

Dezimale

8.38905 \dots

Schritte zur Lösung

\int_{0}^{2} e^{x} x d x

Wende die partielle Integration an

= [e^{x} x - \int e^{x} d x]_{0}^{2}

\int e^{x} d x = e^{x}

= [e^{x} x - e^{x}]_{0}^{2}

Berechne die Grenzen:

e^{2} + 1

= e^{2} + 1

\int_{0}^{2} 4 + x^{2}^{3} d x

\int_{0}^{5} 6 e^{3 x} d x

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