integral from 0 to 1 of e-e^x

Lösung

\int_{0}^{1} e - e^{x} d x

1

Schritte zur Lösung

\int_{0}^{1} e - e^{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} e d x - \int_{0}^{1} e^{x} d x

\int_{0}^{1} e d x = e

\int_{0}^{1} e^{x} d x = e - 1

= e - (e - 1)

Vereinfache

= 1

\int_{- 1}^{2} (x - 1) (x + 1) d x

\int_{0}^{3} \frac{x}{16 + 3 x} d x

\int_{0}^{x} x^{4} + x^{6} d x

\int_{0}^{1} x^{3} + x d x

\int_{0}^{a r c t a n (3)} sin (2 x) d x