integral from 1 to 2 of 4x^3-6x

Lösung

\int_{1}^{2} 4 x^{3} - 6 x d x

6

Schritte zur Lösung

\int_{1}^{2} 4 x^{3} - 6 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 4 x^{3} d x - \int_{1}^{2} 6 x d x

\int_{1}^{2} 4 x^{3} d x = 15

\int_{1}^{2} 6 x d x = 9

= 15 - 9

Vereinfache

= 6

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