integral from 1 to 2 of (x^2+x)

Lösung

\int_{1}^{2} (x^{2} + x) d x

\frac{23}{6}

Dezimale

3.83333 \dots

Schritte zur Lösung

\int_{1}^{2} x^{2} + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} x d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} x d x = \frac{3}{2}

= \frac{7}{3} + \frac{3}{2}

Vereinfache

\frac{7}{3} + \frac{3}{2} : \frac{23}{6}

= \frac{23}{6}

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