integral from 17 to x of 1/t

Lösung

\int_{17}^{x} \frac{1}{t} d t

ln ∣ x ∣ - ln (17)

Schritte zur Lösung

\int_{17}^{x} \frac{1}{t} d t

Nutze das gemeinsame Integral :

\int \frac{1}{t} d t = ln (∣ t ∣)

= [ln ∣ t ∣]_{17}^{x}

Berechne die Grenzen:

ln ∣ x ∣ - ln (17)

= ln ∣ x ∣ - ln (17)

\int_{x}^{1} sin^{2} (t) d t

\int_{- 1}^{1} t^{3} d t

\int_{0}^{2} t 1 + 4 t^{2} d t

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\int_{0}^{\frac{π}{2}} 3 (sin (x))^{3} d x