integral from 0 to 1-x-y of z

Lösung

\int_{0}^{1 - x - y} z d z

\frac{( 1 - x - y ) ^{2}}{2}

Schritte zur Lösung

\int_{0}^{1 - x - y} z d z

Wende die Potenzregel an

= [\frac{z ^{2}}{2}]_{0}^{1 - x - y}

Berechne die Grenzen:

\frac{( 1 - x - y ) ^{2}}{2}

= \frac{( 1 - x - y ) ^{2}}{2}

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