integral from 1 to x^2 of 1/(t^4)

Lösung

\int_{1}^{x^{2}} \frac{1}{t ^{4}} d t

- \frac{1}{3 x ^{6}} + \frac{1}{3}

Schritte zur Lösung

\int_{1}^{x^{2}} \frac{1}{t ^{4}} d t

Wende die Potenzregel an

= [- \frac{1}{3 t ^{3}}]_{1}^{x^{2}}

Berechne die Grenzen:

- \frac{1}{3 x ^{6}} + \frac{1}{3}

= - \frac{1}{3 x ^{6}} + \frac{1}{3}

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