integral from 4 to 1 of x

Lösung

\int_{4}^{1} x d x

- \frac{15}{2}

Dezimale

- 7.5

Schritte zur Lösung

\int_{4}^{1} x d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{4} x d x

Wende die Potenzregel an

= - [\frac{x ^{2}}{2}]_{1}^{4}

Berechne die Grenzen:

\frac{15}{2}

= - \frac{15}{2}

\int_{6}^{7} 13 x - x^{2} - 42 d x

\int_{0}^{2} 5^{2 x} d x

\int_{1}^{2} cos (2 θ) cos (3 θ) d θ

\int_{1}^{4} x^{2} - 2 x - 3 d x

\int_{0}^{a} 1 - \frac{x ^{2}}{a ^{2}} d x