integral from 0 to 2pi of 12

Lösung

\int_{0}^{2 π} 12 d t

24 π

Dezimale

75.39822 \dots

Schritte zur Lösung

\int_{0}^{2 π} 12 d t

Integral einer Konstanten :

\int a d x = a x

= [12 t]_{0}^{2 π}

Berechne die Grenzen:

24 π

= 24 π

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