integral from 0 to 1 of sin(t)

Lösung

\int_{0}^{1} sin (t) d t

- cos (1) + 1

Dezimale

0.45969 \dots

Schritte zur Lösung

\int_{0}^{1} sin (t) d t

Nutze das gemeinsame Integral :

\int sin (t) d t = - cos (t)

= [- cos (t)]_{0}^{1}

Berechne die Grenzen:

- cos (1) + 1

= - cos (1) + 1

\int_{1}^{3} (2 - x)^{2} d x

\int_{0}^{4} (\frac{1}{2 x + 1}) d x

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\int_{0}^{2} e^{- y} d y

\int_{1}^{4} \frac{1}{x} - \frac{1}{x ^{2}} d x