integral from-1 to 1 of 2y^2-2

Lösung

\int_{- 1}^{1} 2 y^{2} - 2 d y

- \frac{8}{3}

Dezimale

- 2.66666 \dots

Schritte zur Lösung

\int_{- 1}^{1} 2 y^{2} - 2 d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 y^{2} d y - \int_{- 1}^{1} 2 d y

\int_{- 1}^{1} 2 y^{2} d y = \frac{4}{3}

\int_{- 1}^{1} 2 d y = 4

= \frac{4}{3} - 4

Vereinfache

\frac{4}{3} - 4 : - \frac{8}{3}

= - \frac{8}{3}

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