integral from 0 to 4 of (5x+sqrt(x))

Lösung

\int_{0}^{4} (5 x + x) d x

\frac{136}{3}

Dezimale

45.33333 \dots

Schritte zur Lösung

\int_{0}^{4} 5 x + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 5 x d x + \int_{0}^{4} x d x

\int_{0}^{4} 5 x d x = 40

\int_{0}^{4} x d x = \frac{16}{3}

= 40 + \frac{16}{3}

Vereinfache

40 + \frac{16}{3} : \frac{136}{3}

= \frac{136}{3}

\int_{0}^{1} x^{16} + 1 6^{x} d x

\int_{0}^{\infty} e^{- r^{2}} r d r

\int_{0}^{3} r^{2} d r

\int_{y}^{π} cos (x^{2}) d x

\int_{0}^{3} (x^{2} + 3 x) d x