integral from-1 to 0 of 2x-1

Lösung

\int_{- 1}^{0} 2 x - 1 d x

- 2

Schritte zur Lösung

\int_{- 1}^{0} 2 x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 2 x d x - \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} 2 x d x = - 1

\int_{- 1}^{0} 1 d x = 1

= - 1 - 1

Vereinfache

= - 2

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