integral from 0 to x of xe^x

Lösung

\int_{0}^{x} x e^{x} d x

e^{x} x - e^{x} + 1

Schritte zur Lösung

\int_{0}^{x} x e^{x} d x

Wende die partielle Integration an

= [e^{x} x - \int e^{x} d x]_{0}^{x}

\int e^{x} d x = e^{x}

= [e^{x} x - e^{x}]_{0}^{x}

Berechne die Grenzen:

e^{x} x - e^{x} + 1

= e^{x} x - e^{x} + 1

\int_{0}^{7} e^{x} d x

\int_{0}^{2} (6 x - 9) (8 x^{2} + 4) d x

\int_{0}^{1} \frac{2}{1 - x ^{2}} d x

\int_{- 1}^{0} x^{4} d x

\int_{1}^{2} \frac{v ^{3} + 5 v ^{8}}{v ^{4}} d v