integral from 1 to 3 of 1/(x-1)

Lösung

\int_{1}^{3} \frac{1}{x - 1} d x

divergiert

Schritte zur Lösung

\int_{1}^{3} \frac{1}{x - 1} d x

Wende U-Substitution an

= \int_{0}^{2} \frac{1}{u} d u

Nutze das gemeinsame Integral :

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{0}^{2}

Berechne die Grenzen:

divergiert

= divergiert

\int_{- 5}^{c o s (x)} \frac{1}{t ^{2} - 1} d t

\int_{- 2}^{2} (∣ x ∣ + x) e^{∣ x ∣} d x

\int_{1}^{4} x^{- 3} d x

\int_{7}^{8} (\frac{3}{x ^{2}} - 1) d x

\int_{0}^{5} (2 x + 5) d x