integral from 0 to x of 3/4 x(2-x)

Lösung

\int_{0}^{x} \frac{3}{4} x (2 - x) d x

\frac{3}{4} x^{2} - \frac{x ^{3}}{4}

Schritte zur Lösung

\int_{0}^{x} \frac{3}{4} x (2 - x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{4} \cdot \int_{0}^{x} x (2 - x) d x

Multipliziere aus

x (2 - x) : 2 x - x^{2}

= \frac{3}{4} \cdot \int_{0}^{x} 2 x - x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{3}{4} (\int_{0}^{x} 2 x d x - \int_{0}^{x} x^{2} d x)

\int_{0}^{x} 2 x d x = x^{2}

\int_{0}^{x} x^{2} d x = \frac{x ^{3}}{3}

= \frac{3}{4} (x^{2} - \frac{x ^{3}}{3})

Vereinfache

\frac{3}{4} (x^{2} - \frac{x ^{3}}{3}) : \frac{3}{4} x^{2} - \frac{x ^{3}}{4}

= \frac{3}{4} x^{2} - \frac{x ^{3}}{4}

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