integral from 1 to ln(8) of e^y(y-1)

Lösung

\int_{1}^{l n (8)} e^{y} (y - 1) d y

24 ln (2) - 16 + e

Dezimale

3.35381 \dots

Schritte zur Lösung

\int_{1}^{l n (8)} e^{y} (y - 1) d y

Wende die partielle Integration an

= [e^{y} (y - 1) - \int e^{y} d y]_{1}^{3 l n (2)}

\int e^{y} d y = e^{y}

= [e^{y} (y - 1) - e^{y}]_{1}^{3 l n (2)}

Multipliziere aus

e^{y} (y - 1) - e^{y} : e^{y} y - 2 e^{y}

= [e^{y} y - 2 e^{y}]_{1}^{3 l n (2)}

Berechne die Grenzen:

24 ln (2) - 16 + e

= 24 ln (2) - 16 + e

\int_{- 2}^{1} 4 x + 8 d x

\int_{0}^{1} (3 x) d x

\int_{- 3}^{2} - 3 ∣ x ∣ d x

\int_{- 1}^{1} x^{299} d x

\int_{0}^{3} x^{2} - x d x