integral from-2 to 4 of 10+4x-3x^3

Lösung

\int_{- 2}^{4} 10 + 4 x - 3 x^{3} d x

- 96

Schritte zur Lösung

\int_{- 2}^{4} 10 + 4 x - 3 x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{4} 10 d x + \int_{- 2}^{4} 4 x d x - \int_{- 2}^{4} 3 x^{3} d x

\int_{- 2}^{4} 10 d x = 60

\int_{- 2}^{4} 4 x d x = 24

\int_{- 2}^{4} 3 x^{3} d x = 180

= 60 + 24 - 180

Vereinfache

= - 96

\int x - \frac{x}{x ^{2} + 1} d x

\int \frac{5 x + 1}{6 x ^{2} + 7 x - 3} d x

\int sin (x) + 1 d x

\int \frac{1}{( 4 x ^{2} + 9 ) ^{\frac{3}{2}}} d x

n = 0 \sum \infty 1 + 2 + 3 + 4 + 5