What is the derivative of y=2x^{-3} ?

The derivative of y=2x^{-3} is -6/(x^4)

What is the first derivative of y=2x^{-3} ?

The first derivative of y=2x^{-3} is -6/(x^4)

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derivative of

y = 2 x^{- 3}

- \frac{6}{x ^{4}}

Solution steps

\frac{d}{d x} (2 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 3 x^{- 3 - 1})

Simplify

2 (- 3 x^{- 3 - 1}) : - \frac{6}{x ^{4}}

= - \frac{6}{x ^{4}}

\frac{d y}{d x} = (\frac{1}{1 + x ^{2}})

x \to 4 - lim (\frac{x - 10}{x - 4})

\frac{d}{d x} (x^{\frac{2}{3}} (x + 2))

\frac{\partial}{\partial y} (\frac{1}{2 - x + y})

What is the derivative of y=2x^{-3} ?
The derivative of y=2x^{-3} is -6/(x^4)
What is the first derivative of y=2x^{-3} ?
The first derivative of y=2x^{-3} is -6/(x^4)