What is the integral from 1 to infinity of 1/x ?

The integral from 1 to infinity of 1/x is diverges

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integral from 1 to infinity of 1/x

\int_{1}^{\infty} \frac{1}{x} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{x} d x

Compute the indefinite integral:

\int \frac{1}{x} d x = ln ∣ x ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{x} d x =

diverges

= diverges

(0, 2), (- 5, - 1)

n = 1 \sum \infty \frac{1}{2 ^{n + 1}}

e^{- s} \frac{1}{s - 4}

x \to \infty + lim (\frac{2 x + 1}{4 x ^{2} + x})

\frac{y}{x} \cdot \frac{d y}{d x} = - 4 - \frac{y ^{2}}{x ^{2}}

What is the integral from 1 to infinity of 1/x ?
The integral from 1 to infinity of 1/x is diverges