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Beliebt Rechnen >

sum from n=1 to infinity of (-2/3)^n

Lösung

n = 1 \sum \infty (- \frac{2}{3})^{n}

Lösung

- \frac{2}{5}

+1

Dezimale

- 0.4

Schritte zur Lösung

n = 1 \sum \infty (- \frac{2}{3})^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty (- \frac{2}{3})^{n} - (- \frac{2}{3})^{0}

n = 0 \sum \infty (- \frac{2}{3})^{n} = \frac{3}{5}

= \frac{3}{5} - (- \frac{2}{3})^{0}

Vereinfache

\frac{3}{5} - (- \frac{2}{3})^{0} : - \frac{2}{5}

= - \frac{2}{5}

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