What is the limit as h approaches 0 of ((pi+h)+1)/h ?

The limit as h approaches 0 of ((pi+h)+1)/h is diverges

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limit as h approaches 0 of ((pi+h)+1)/h

h \to 0 lim (\frac{( π + h ) + 1}{h})

diverges

Solution steps

h \to 0 lim (\frac{π + h + 1}{h})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

h \to 0 + lim (\frac{π + h + 1}{h}) = \infty

h \to 0 - lim (\frac{π + h + 1}{h}) = - \infty

= diverges

\frac{d}{d x} (\frac{( x ^{2} - 3 x )}{4 x + 1})

x, 0, 3

n = 2 \sum \infty \frac{8}{( n ^{2} - 1 )}

y = \frac{e ^{x}}{x}

\int (4 sin (x) - 1 + 8 x^{- 5}) d x

What is the limit as h approaches 0 of ((pi+h)+1)/h ?
The limit as h approaches 0 of ((pi+h)+1)/h is diverges