What is the solution for f^'(x)=3e^{2x^2} ?

The solution for f^'(x)=3e^{2x^2} is f(x)=(3sqrt(pi))/(2^{3/2)}\erfi(sqrt(2)x)+c_{1}

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f^'(x)=3e^{2x^2}

f^{^{'}} (x) = 3 e^{2 x^{2}}

f (x) = \frac{3 π}{2 ^{\frac{3}{2}}} erfi (2 x) + c_{1}

Solution steps

f^{'} (x) = 3 e^{2 x^{2}}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 3 e^{2 x^{2}} d x

\int 3 e^{2 x^{2}} d x = \frac{3 π}{2 2} erfi (2 x) + c_{1}

f (x) = \frac{3 π}{2 2} erfi (2 x) + c_{1}

Simplify

f (x) = \frac{3 π}{2 ^{\frac{3}{2}}} erfi (2 x) + c_{1}

y^{^{'}} = \frac{1 - 4 y ^{2}}{3 x y}

y = - 6 cos (- 2 x)

x \to 0 + lim (x^{\frac{2}{3}})

\int \frac{x ^{2}}{x ^{6} - 5} d x

\frac{d}{d x} (\frac{x}{( x ^{2} - 1 ) ^{4}})

What is the solution for f^'(x)=3e^{2x^2} ?
The solution for f^'(x)=3e^{2x^2} is f(x)=(3sqrt(pi))/(2^{3/2)}\erfi(sqrt(2)x)+c_{1}