What is the integral of (x^3)/(sqrt(u)) ?

The integral of (x^3)/(sqrt(u)) is (x^4)/(4sqrt(u))+C

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integral of (x^3)/(sqrt(u))

\int \frac{x ^{3}}{u} d x

\frac{x ^{4}}{4 u} + C

Solution steps

\int \frac{x ^{3}}{u} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{u} \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= \frac{1}{u} \cdot \frac{x ^{4}}{4}

Simplify

\frac{1}{u} \cdot \frac{x ^{4}}{4} : \frac{x ^{4}}{4 u}

= \frac{x ^{4}}{4 u}

Add a constant to the solution

= \frac{x ^{4}}{4 u} + C

x^{3} - 3 x^{2} + 3

\int_{0}^{17} x d x

cos^{2} (21 t)

y = 2 sin (x), 0, at x = 0

4 x^{2} - 4, x^{4} - 1

What is the integral of (x^3)/(sqrt(u)) ?
The integral of (x^3)/(sqrt(u)) is (x^4)/(4sqrt(u))+C