What is area y=3-x,y=(x^2)/4 ,x=2,x=1 ?

The answer to area y=3-x,y=(x^2)/4 ,x=2,x=1 is 11/12

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area y=3-x,y=(x^2)/4 ,x=2,x=1

area

y = 3 - x, y = \frac{x ^{2}}{4}, x = 2, x = 1

\frac{11}{12}

Decimal Notation

0.91666 \dots

Solution steps

Apply the area formula:

\int_{1}^{2} 3 - x - \frac{x ^{2}}{4} d x

Solve

\int_{1}^{2} 3 - x - \frac{x ^{2}}{4} d x : \frac{11}{12}

The area is:

= \frac{11}{12}

3 y^{^{''}} + 2 y = 5 e^{2 x} + 2 x^{3}

\int \frac{3}{2 x ^{2}} d x

75 (1 - \frac{8}{x})

x y y^{^{'}} - y^{2} = y^{2} \frac{y}{x}

\int \frac{x ^{2} - 81}{x ^{4}} d x

What is area y=3-x,y=(x^2)/4 ,x=2,x=1 ?
The answer to area y=3-x,y=(x^2)/4 ,x=2,x=1 is 11/12