What is the solution for (dy)/(dt)=tsqrt(y) ?

The solution for (dy)/(dt)=tsqrt(y) is y=(t^4}{16}+\frac{c_{1}t^2)/4+(c_{1}^2)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)=tsqrt(y)

\frac{d y}{d t} = t y

y = \frac{t ^{4}}{16} + \frac{c _{1} t ^{2}}{4} + \frac{c _{1}^{2}}{4}

Solution steps

\frac{d y}{d t} = t y

Solve separable ODE:

y = \frac{t ^{4}}{16} + \frac{c _{1} t ^{2}}{4} + \frac{c _{1}^{2}}{4}

y = \frac{t ^{4}}{16} + \frac{c _{1} t ^{2}}{4} + \frac{c _{1}^{2}}{4}

\frac{d y}{d x}, y = 5 x

x^{2} y^{^{''}} - 7 x y^{^{'}} + 7 y = 13 x^{\frac{1}{2}}

\frac{\partial}{\partial y} ((x^{2} - y^{2}) e^{- x^{2} - y^{2}})

x \to - \infty lim (3^{2 x})

y \frac{d y}{d x} = 3 x y^{2} + 9 x

What is the solution for (dy)/(dt)=tsqrt(y) ?
The solution for (dy)/(dt)=tsqrt(y) is y=(t^4}{16}+\frac{c_{1}t^2)/4+(c_{1}^2)/4