What is (\partial)/(\partial x)(-5ycos(9x)) ?

The answer to (\partial)/(\partial x)(-5ycos(9x)) is 45ysin(9x)

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(\partial)/(\partial x)(-5ycos(9x))

\frac{\partial}{\partial x} (- 5 y cos (9 x))

45 y sin (9 x)

Solution steps

\frac{\partial}{\partial x} (- 5 y cos (9 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 y \frac{\partial}{\partial x} (cos (9 x))

Apply the chain rule:

- sin (9 x) \frac{\partial}{\partial x} (9 x)

= - sin (9 x) \frac{\partial}{\partial x} (9 x)

\frac{\partial}{\partial x} (9 x) = 9

= - 5 y (- sin (9 x) \cdot 9)

Simplify

= 45 y sin (9 x)

x \to 3 lim (5 x^{2} - 9 x + 7)

f (x) = x + 6

\int \frac{1}{81 e ^{- 9 x} + e ^{9 x}} d x

\int_{- 2}^{3} \frac{29}{x ^{4}} d x

sin^{2} (3 - 6 x)

What is (\partial)/(\partial x)(-5ycos(9x)) ?
The answer to (\partial)/(\partial x)(-5ycos(9x)) is 45ysin(9x)