What is (\partial)/(\partial y)(2x^4y-1) ?

The answer to (\partial)/(\partial y)(2x^4y-1) is 2x^4

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(\partial)/(\partial y)(2x^4y-1)

\frac{\partial}{\partial y} (2 x^{4} y - 1)

2 x^{4}

Solution steps

\frac{\partial}{\partial y} (2 x^{4} y - 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{4} y) - \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (2 x^{4} y) = 2 x^{4}

\frac{\partial}{\partial y} (1) = 0

= 2 x^{4} - 0

Simplify

= 2 x^{4}

\int (cos (x) + 2 cos (2 x))^{2} d x

f (x) = 10 x sin (x), at x = \frac{π}{2}

\frac{\partial}{\partial x} (\frac{1}{4 - x ^{2}})

x \to 0 lim (\frac{x ^{2}}{x ^{4}})

\frac{d}{d x} (x^{3} - 3 x^{2} - 8 x + 2)

What is (\partial)/(\partial y)(2x^4y-1) ?
The answer to (\partial)/(\partial y)(2x^4y-1) is 2x^4