What is the tangent of f(x)=4x^3-4x,(1,0) ?

The tangent of f(x)=4x^3-4x,(1,0) is y=8x-8

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tangent of f(x)=4x^3-4x,(1,0)

tangent of

f (x) = 4 x^{3} - 4 x, (1, 0)

y = 8 x - 8

Solution steps

Find the slope of

f (x) = 4 x^{3} - 4 x : \frac{df ( x )}{d x} = 12 x^{2} - 4

Compute the slope of

f (x) = 4 x^{3} - 4 x

(1, 0) : m = 8

Find the line with slope m=

8

and passing through

(1, 0) : y = 8 x - 8

y = 8 x - 8

y = 4 x^{3} - 9 x^{2} - 12 x + 12, (1, - 5)

\frac{d}{d x} (\frac{tan ( x ) - 1}{sec ( x )})

\frac{d}{d x} (2 arccos (\frac{x}{4}))

What is the tangent of f(x)=4x^3-4x,(1,0) ?
The tangent of f(x)=4x^3-4x,(1,0) is y=8x-8